Java Program To Calculate Power Of Number | 4 Ways

in Java Programs, Uncategorized April 16, 2025 Comments Off on Java Program To Calculate Power Of Number | 4 Ways

Java Program To Calculate Power Of Number – In this article, we will detail in on the several ways to calculate the power of a number in Java programming.

Suitable examples and sample programs have also been added so that you can understand the whole thing very clearly. The compiler has also been added with which you can execute it yourself.

The several methods used in this specific piece are as follows:

Using Standard Method
Using For Loop
Using Command Line Arguments
Using Function
Using Class
Using Recursion

As we all know, the power of a number is the times a number is multiplied with itself. The power of a number, in more simpler terms, is the number of times you have to multiply the number by itself.

For example, 5^3 is called as 5 to the power of 3.

Here, 5^3 = 5*5*5 = 125.

Similarly, 5^(-2) = (1/5)^2 = 1/25.

The power of 0 will always give the result as 1, no matter what the number is, unless if it is undefined or infinite.

As given in the photo above, the powers of the number 11 from 0 to 11 are mentioned there. It is clearly seen that 11 is multiplied by the result once after the other as the power increases.

Thus, the manifold ways to calculate the power of a number in Java programming are as follows:

Using Standard Method

import java.util.Scanner;
{
  public static void main(String arg[])	
  {
    int n=5,p=3,result=1;

    if(n>=0&&p==0)
     {
        result=1;
     }
    else if(n==0&&p>=1)
      { 
         result=0;
      }
    else
     {
         for(int i=1;i<=p;i++)
	 {
            result=result*n;
 	 }	    
     }
    System.out.println(n+"^"+p+"="+result);
	
  }
}

import java.util.Scanner;

{

public static void main(String arg[])

{

int n=5,p=3,result=1;

if(n>=0&&p==0)

{

result=1;

}

else if(n==0&&p>=1)

{

result=0;

}

else

{

for(int i=1;i<=p;i++)

{

result=result*n;

}

System.out.println(n+"^"+p+"="+result);

}

Output:

5^3=125

5^3=125

Using For Loop

java.util.Scanner;
class Power
{
   public static void main(String arg[])
	
   {
	
       long n,p,r=1;
	
       Scanner sc=new Scanner(System.in);

       System.out.println("enter number");
	  
       n=sc.nextLong();

       System.out.println("enter power");
	  
       p=sc.nextLong();

       if(n>=0&&p==0)
       {   
          r =1;
       }
       else if(n==0&&p>=1)
	{   
            r=0;
	} 
       else
	{ 
              for(int i=1;i<=p;i++)
	       { 
                   r=r *n;
 	 	}    
  	 }    
 
    	  System.out.println(n+"^"+p+"="+r);

    }

}

java.util.Scanner;

class Power

{

public static void main(String arg[])

{

long n,p,r=1;

Scanner sc=new Scanner(System.in);

System.out.println("enter number");

n=sc.nextLong();

System.out.println("enter power");

p=sc.nextLong();

if(n>=0&&p==0)

{

r =1;

}

else if(n==0&&p>=1)

{

r=0;

}

else

{

for(int i=1;i<=p;i++)

{

r=r *n;

}

System.out.println(n+"^"+p+"="+r);

}

Output:

1.
  enter number
  6
  enter power
  6
  6^6=46656

2.
  enter number
  8
  enter power
  9
  8^9=134217728

enter number

enter power

6^6=46656

enter number

enter power

8^9=134217728

Using Command Line Arguments

java.util.Scanner;
class Power
{
public static void main(String args[])
{
   long n,p,r=1;

   n=Long.parseLong(args[0]);

   p=Long.parseLong(args[1]);

   if(n>=0&&p==0)
   {
     r =1;
   }
   else if(n==0&&p>=1)
   {
    r=0;
   }
    else
    {
       for(int i=1;i<=p;i++)
       {
            r=r *n;
        }
     }

    System.out.println(n+"^"+p+"="+r);
}
}

java.util.Scanner;

class Power

{

public static void main(String args[])

{

long n,p,r=1;

n=Long.parseLong(args[0]);

p=Long.parseLong(args[1]);

if(n>=0&&p==0)

{

r =1;

}

else if(n==0&&p>=1)

{

r=0;

}

else

{

for(int i=1;i<=p;i++)

{

r=r *n;

}

System.out.println(n+"^"+p+"="+r);

}

Output:

javac Power.java
java Power 4 5
4^5=1024

javac Power.java
java Power 0 0
0^0=1

javac Power.java
java Power 0 1
0^1=0

javac Power.java
java Power 100 20
100^20=-5047021154770878464

javac Power.java
java Power 100 3
100^3=1000000

javac Power.java

java Power 4 5

4^5=1024

javac Power.java

java Power 0 0

0^0=1

javac Power.java

java Power 0 1

0^1=0

javac Power.java

java Power 100 20

100^20=-5047021154770878464

javac Power.java

java Power 100 3

100^3=1000000

Using Function

java.util.Scanner;
class Power
{
  public static void main(String args[])
  {

    long n,p,r=1;

     Scanner sc=new Scanner(System.in);

     System.out.println("enter number");

     n=sc.nextLong();
  
     System.out.println("enter power");

     p=sc.nextLong();

     r=Power.calpower(n,p);

     System.out.println(n+"^"+p+"="+r);

  }

  static long calpower(long n1,long p1)
  {

     long r1=1;

     if(n1>=0&&p1==0)
     
        r1 =1;

     else if(n1==0&&p1>=1)

        r1=0;
     else

       for(int i=1;i<=p1;i++)
       
         r1=r1 *n1;

     return r1;

    }

}

java.util.Scanner;

class Power

{

public static void main(String args[])

{

long n,p,r=1;

Scanner sc=new Scanner(System.in);

System.out.println("enter number");

n=sc.nextLong();

System.out.println("enter power");

p=sc.nextLong();

r=Power.calpower(n,p);

System.out.println(n+"^"+p+"="+r);

}

static long calpower(long n1,long p1)

{

long r1=1;

if(n1>=0&&p1==0)

r1 =1;

else if(n1==0&&p1>=1)

r1=0;

else

for(int i=1;i<=p1;i++)

r1=r1 *n1;

return r1;

}

Output:

enter number
51
enter power
6
51^6=17596287801

enter number

enter power

51^6=17596287801

Using Class

java.util.Scanner;
class Pow
{
   long r1=1;

   Pow(long n1,long p1)
  {

    if(n1>=0&&p1==0)
    r1 =1;
    else if(n1==0&&p1>=1)
    r1=0;
    else
      for(int i=1;i<=p1;i++)
        r1=r1 *n1;
  }
}
class Power
{
   public static void main(String args[])
   {

    long n,p;

    Scanner sc=new Scanner(System.in);

    System.out.println("enter number");

    n=sc.nextLong();
 
    System.out.println("enter power");

    p=sc.nextLong();

    Pow k=new Pow(n,p);

   System.out.println(n+"^"+p+"="+k.r1);

   }
}

java.util.Scanner;

class Pow

{

long r1=1;

Pow(long n1,long p1)

{

if(n1>=0&&p1==0)

r1 =1;

else if(n1==0&&p1>=1)

r1=0;

else

for(int i=1;i<=p1;i++)

r1=r1 *n1;

}

class Power

{

public static void main(String args[])

{

long n,p;

Scanner sc=new Scanner(System.in);

System.out.println("enter number");

n=sc.nextLong();

System.out.println("enter power");

p=sc.nextLong();

Pow k=new Pow(n,p);

System.out.println(n+"^"+p+"="+k.r1);

}

Output:

enter number
6
enter power
5
6^5=7776

enter number

enter power

6^5=7776

Using Recursion

java.util.Scanner;
class Power
{
   static long r=1;
   public static void main(String arg[])
   {
      long n,p;
      
      Scanner sc=new Scanner(System.in);

      System.out.println("enter number");

      n=sc.nextLong();

      System.out.println("enter power");

      p=sc.nextLong();

      Power.pow(n,p);

      System.out.println(n+"^"+p+"="+r);
   }

 static void  pow(long n,long p)
 {

    if(p<=0)
    {
       return;
    }
     else if(n==0 && p>=1)
    { 
       r=0;
       return;
    }
    else
       r=r*n;

    Power.pow(n,p-1);
}

}

java.util.Scanner;

class Power

{

static long r=1;

public static void main(String arg[])

{

long n,p;

Scanner sc=new Scanner(System.in);

System.out.println("enter number");

n=sc.nextLong();

System.out.println("enter power");

p=sc.nextLong();

Power.pow(n,p);

System.out.println(n+"^"+p+"="+r);

}

static void pow(long n,long p)

{

if(p<=0)

{

return;

}

else if(n==0 && p>=1)

{

r=0;

return;

}

else

r=r*n;

Power.pow(n,p-1);

}

Output:

enter number
5
enter power
5
5^5=3125

enter number

enter power

5^5=3125

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Java Program To Calculate Power Of Number | 4 Ways

Using Standard Method

Using For Loop

Using Command Line Arguments

Using Function

Using Class

Using Recursion

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