Beginners Programs :

Insertion Sort Java Algorithm – 2 Ways | Java Sortings

Implement Insertion Sort Algorithm In Java – We will discuss the various methods to Implement Insertion Sort Algorithm In Java. Compiler has been added so that you can execute the programs easily, alongside suitable examples and sample outputs. The methods are – Also check Heap Sort In Java

  • Algorithm – Using Array.
  • Algorithm – Using Buffered Reader.

Insertion Sort Java – Using Array

1) We are using array for insertion sort.

2) The print method will print the array elements, sort method will sort the array elements.

3) The elements in the array are 9, 5, 0, 1, 8.

For 1st iteration the inner loop compares the number with previous number, if previous number is greater than this number then shift the least number to left.

For i=1,  inner loop compares the numbers 5<9, then 5 will be shifted to left. Then the series is 5, 9, 0, 1, 8. In this sorted sub array is 5,9.

For i=2, the inner loop compares the numbers 0<9, shift 0 to left, compare 0<5, shift 0 to left. Then the sorted sub array is 0, 5, 9. The series is 0, 5, 9, 1, 8.

For i=3, inner loop will compare the numbers 1<9, shift 1 to left, compare 1<5, shift 1 to left, compare 1,0. The sorted sub array is 0, 1, 5, 9 and the series is 0, 1, 5, 9, 8.

For i=4, inner loop will compare the numbers 8<9, shift 8 to left. The sorted series is 0, 1, 5, 8, 9.

Output:

Insertion Sort Using Buffered Reader

1) Buffered Reader reads the data from character based input stream. In this program, InputStreamReader is the character based input stream.

2) Using readLine() method read the data, parseInt() method converts the data in to integer value and store the numbers in to the array a[].

The given series is 10, 2, 1, 56, 48, 11.

3) For each iteration of i, the inner loop will generate a sub sorted array in which the least number is shifted to left by comparing with previous numbers.

4) 1st iteration of i, compare 10,2 and 2 shifted to left. Then the sorted sub array is 2, 10.

  • 2nd iteration of i,compare 10,1 and shift 1 to left.compare 2,1 and shift 1 to left, then the sorted sub array is 1, 2, 10.
  • 3rd iteration of i, compare 56 with the previous numbers of sorted sub array, then the sorted sub array is 1, 2, 10, 56.
  • 4th iteration of i, compare 48 with previous numbers of sorted sub array, then the sub array is 1, 2, 10, 48, 56.
  • 5th iteration of i, compare 11 with the previous numbers of the sub array, then the sorted array is 1, 2, 10, 11, 48, 56.

Output:

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